Question:

For the given reaction :

What is 'A'?

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NaNH2 dehydrohalogenates the vinyl bromide to propyne; a red hot iron tube trimerises it to a benzene derivative.
Updated On: Nov 4, 2026
  • \(\mathrm{CH_3CH_2CH_2NH_2}\)
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The Correct Option is A

Solution and Explanation

The reactant is 1-bromopropene, CH3-CH=CHBr.
Step 1: NaNH2 (strong base) removes HBr (dehydrohalogenation) to give propyne, CH3-C\(\equiv\)CH.
Step 2: alkynes undergo cyclic polymerisation when passed through a red hot iron tube at 873 K. Three molecules of propyne give 1,3,5-trimethylbenzene (mesitylene).
Option (2) is benzene (from ethyne), option (3) is an enamine and (4) is propylamine, neither of which can form.
Answer: (1) 1,3,5-trimethylbenzene
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