For the following Assertion and Reason, the correct option is
Assertion : For hydrogenation reactions, the catalytic activity increases from Group 5 to Group 11 metals with maximum activity shown by Group 7-9 elements.
Reason : The reactants are most strongly adsorbed on group 7-9 elements.
Assertion : For hydrogenation reactions, the catalytic activity increases from Group 5 to Group 11 metals with maximum activity shown by Group 7-9 elements.
Reason : The reactants are most strongly adsorbed on group 7-9 elements.
Show Hint
- Both assertion and reason are true and the reason is the correct explanation for the assertion.
- The assertion is true, but the reason is false.
- Both assertion and reason are true but the reason is not the correct explanation for the assertion.
- Both assertion and reason are false.
The Correct Option is B
Solution and Explanation
Reason: the metals that adsorb the reactants most strongly are the early transition metals (Groups 5-6). A catalyst must adsorb the reactants moderately (strongly enough to activate them but weakly enough to let the product desorb). Group 7-9 metals have an intermediate adsorption strength, which gives the volcano-shaped activity curve. So the Reason is false.
Hence the assertion is true but the reason is false.
Answer: (2) The assertion is true, but the reason is false.
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
Top JEE Main Catalysis Questions
- The variation of the rate of an enzyme catalyzed reaction with substrate concentration is correctly represented by graph
- Some drugs bind to a site other than, theactive site of an enzyme This site is knownas
- Given below are two statements.
Statement I: Iron (III) catalyst, acidified \(K_2Cr_2O_7\) and neutral \(KMnO_4\) have the ability to oxidise \(I^–\) to \(I_2\) independently.
Statement II: Manganate ion is paramagnetic in nature and involves \(pπ – pπ\) bonding.
In the light of the above statements, choose the correct answer from the options given below. - Which of the following is not an example of heterogenous catalytic reaction?
- Match the catalysts (Column I) with products (Column II).
Column I Column II (A) \(\mathrm{V_2O_5}\) (i) Polyethylene (B) \(\mathrm{TiCl_4/Al(Me)_3}\) (ii) ethanal (C) \(\mathrm{PdCl_2}\) (iii) \(\mathrm{H_2SO_4}\) (D) Iron Oxide (iv) \(\mathrm{NH_3}\)
Top JEE Main Questions
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,