Question

For the array \texttt{U[][] = \{\{4, 5\, \{7, 2\}, \{19, 4\}, \{7, 43\}\}}, find the maximum element and the index of the minimum element.}

Hint:

In Java 2D arrays, indexing starts from \(0\). So the first row is row \(0\) and the first column is column \(0\).

Answer 1

Step 1: Write all the elements of the array.
The given 2D array is:
\[ \begin{bmatrix} 4 & 5 \\ 7 & 2 \\ 19 & 4\\ 7 & 43 \end{bmatrix} \] Step 2: Find the maximum element.
Now compare all the elements:
\[ 4,\ 5,\ 7,\ 2,\ 19,\ 4,\ 7,\ 43 \] The greatest value among these is:
\[ 43 \] Step 3: Find the minimum element.
The smallest value in the array is:
\[ 2 \] Step 4: Find the index of the minimum element.
In Java, array indexing starts from \(0\).
The element \(2\) is present in the second row and second column, so its index is:
\[ [1][1] \] Step 5: State the final answer.
Therefore:
\[ \boxed{\text{Maximum element} = 43} \] and
\[ \boxed{\text{Index of minimum element} = [1][1]} \]