For reaction $A \rightleftharpoons B$, $\Delta G^{\circ} = 105 - 35 \log T$. Find the transition temperature (in $^{\circ} C$) of the above reaction at 1 bar.
The transition temperature is the temperature at which the system is at equilibrium between two states, which implies $\Delta G^{\circ} = 0$. 1. Set equilibrium condition: At transition temperature, $\Delta G^{\circ} = 0$.
2. Solve for T: $105 - 35 \log T = 0$ $35 \log T = 105$ $\log T = \frac{105}{35} = 3$ $T = 10^3 = 1000 \text{ K}$
3. Convert to Celsius: $t = T - 273$ $t = 1000 - 273 = 727^{\circ} C$