For per gram of reactant, the maximum quantity of N2 gas is produced in which of the following thermal decomposition reactions ?
(Given : Atomic wt. - Cr = 52 u, Ba = 137 u)
(Given : Atomic wt. - Cr = 52 u, Ba = 137 u)
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- \((\mathrm{NH_4})_2\mathrm{Cr_2O_7}(s) \to \mathrm{N_2}(g) + 4\mathrm{H_2O}(g) + \mathrm{Cr_2O_3}(s)\)
- \(2\mathrm{NH_4NO_3}(s) \to 2\mathrm{N_2}(g) + 4\mathrm{H_2O}(g) + \mathrm{O_2}(g)\)
- \(\mathrm{Ba(N_3)_2}(s) \to \mathrm{Ba}(s) + 3\mathrm{N_2}(g)\)
- \(2\mathrm{NH_3}(g) \to \mathrm{N_2}(g) + 3\mathrm{H_2}(g)\)
The Correct Option is D
Solution and Explanation
(1) (NH4)2Cr2O7: M = 2(18) + 2(52) + 7(16) = 252 g. \(1/252 = 3.97\times10^{-3}\).
(2) 2NH4NO3: M = 2 × 80 = 160 g. \(2/160 = 1.25\times10^{-2}\).
(3) Ba(N3)2: M = 137 + 84 = 221 g. \(3/221 = 1.36\times10^{-2}\).
(4) 2NH3: M = 2 × 17 = 34 g. \(1/34 = 2.94\times10^{-2}\).
The largest value is for reaction (4).
Answer: (4) \(2\mathrm{NH_3}(g) \to \mathrm{N_2}(g) + 3\mathrm{H_2}(g)\)
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