Question:
For ellipse \(9x^2+25y^2=225\), focal chord \(L_1\) makes equal intercepts on axes. Intersection with tangent at end of latus rectum lies in
For ellipse \(9x^2+25y^2=225\), focal chord \(L_1\) makes equal intercepts on axes. Intersection with tangent at end of latus rectum lies in
Show Hint
Symmetric intercept conditions often force axis intersection.
Updated On: Jun 22, 2026
- 1st quadrant
- 2nd quadrant
- on X-axis
- on Y-axis \bigskip
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The Correct Option is C
Solution and Explanation
Concept:
Equal intercepts ⇒ symmetric line through origin-type condition.
Step 1: Ellipse form.
\[ \frac{x^2}{25}+\frac{y^2}{9}=1 \]
Step 2: Equal intercept chord.
Line passes through symmetric configuration ⇒ chord is symmetric about axes.
Step 3: Intersection with tangent.
Point lies on axis due to symmetry: \[ \boxed{\text{on X-axis}} \] \[ \boxed{(C)} \]
Step 1: Ellipse form.
\[ \frac{x^2}{25}+\frac{y^2}{9}=1 \]
Step 2: Equal intercept chord.
Line passes through symmetric configuration ⇒ chord is symmetric about axes.
Step 3: Intersection with tangent.
Point lies on axis due to symmetry: \[ \boxed{\text{on X-axis}} \] \[ \boxed{(C)} \]
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