




The flow diagram numbers the states as 1 (condenser exit), 2 (pump exit), 3 (feedwater heated by the bled steam, entering the boiler), 4 (boiler exit, turbine inlet), and 5 (turbine exit, entering the condenser). Because the cycle is called ideal, the pump and the turbine are both taken as reversible, so both processes must run at constant entropy. On a T-s plot that means leg 1 to 2 and leg 4 to 5 must each be drawn as vertical lines, not slanted ones. The heating from 2 to 3 happens because the cold feedwater picks up heat from the extracted steam, so it must show a rise in both temperature and entropy, ending close to the saturated liquid boundary. The heating from 3 to 4 is the boiler adding the rest of the heat at essentially constant high pressure, drawn as the near horizontal top segment, and 5 to 1 is the constant pressure condensation at the bottom.
Only option A keeps both the pump and the turbine as vertical, isentropic legs while still showing a clear separate regeneration step from 2 to 3, so option A is the correct T-s diagram.
