For a particle executing simple harmonic motion (SHM), let's analyze the situation at the mean position (equilibrium point).
The correct answer is (B) Velocity is maximum and acceleration is zero.
In simple harmonic motion (SHM), at the mean position (x = 0), the velocity is at its maximum and the acceleration is zero. The equations for SHM are: \[ V = \omega A \sqrt{1 - (x/A)^2} \] \[ a = -\omega^2 x \] At the mean position, x = 0, so acceleration (a) is zero and velocity is at maximum.
Two simple pendulums having lengths $l_{1}$ and $l_{2}$ with negligible string mass undergo angular displacements $\theta_{1}$ and $\theta_{2}$, from their mean positions, respectively. If the angular accelerations of both pendulums are same, then which expression is correct?
Match the following:
In the following, \( [x] \) denotes the greatest integer less than or equal to \( x \). 
Choose the correct answer from the options given below:
For x < 0:
f(x) = ex + ax
For x ≥ 0:
f(x) = b(x - 1)2