Step 1: Static stability condition.
For an aircraft to be longitudinally statically stable, a small increase in angle of attack (\(\alpha\)) should produce a restoring (nose–down) moment.
- Nose–up moment is defined as positive.
- Hence, with increasing \(\alpha\), \(C_m\) must decrease.
\[
\frac{\partial C_m}{\partial \alpha} < 0
\]
Step 2: Graphical requirement.
The slope of \(C_m\) vs \(\alpha\) should be negative.
That eliminates (A) and (C), because both have positive slope.
Step 3: Distinguish between (B) and (D).
For a real aircraft:
- At \(\alpha = 0\), \(C_m\) is typically not zero; it has a negative (nose–down) or slightly negative constant trim moment to balance lift.
- To trim at some positive \(\alpha\), the line should cross zero at a finite \(\alpha\).
- This corresponds to a line with negative slope and an intercept above the origin.
Option (D) matches this condition.
Final Answer:
\[
\boxed{\text{(D) Negative slope with intercept above origin}}
\]
A jet-powered airplane is steadily climbing at a rate of 10 m/s. The air density is 0.8 kg/m³, and the thrust force is aligned with the flight path. Using the information provided in the table below, the airplane’s thrust to weight ratio is ___________ (rounded off to one decimal place). 
While taking off, the net external force acting on an airplane during the ground roll segment can be assumed to be constant. The airplane starts from rest. \( S_{LO} \) and \( V_{LO} \) are the ground roll distance and the lift-off speed, respectively. \( \alpha V_{LO} \) (\( \alpha>0 \)) denotes the airplane speed at 0.5 \( S_{LO} \). Neglecting changes in the airplane mass during the ground roll segment, the value of \( \alpha \) is _________ (rounded off to two decimal places).