For a dimerization reaction,
\(\mathrm{2A(g) \to A_2(g)}\)
at 298 K, \(\Delta U^\circ = -20\ \mathrm{kJ\ mol^{-1}}\), \(\Delta S^\circ = -30\ \mathrm{J\,K^{-1}\,mol^{-1}}\),
then the \(\Delta G^\circ\) will be _____ J.
\(\mathrm{2A(g) \to A_2(g)}\)
at 298 K, \(\Delta U^\circ = -20\ \mathrm{kJ\ mol^{-1}}\), \(\Delta S^\circ = -30\ \mathrm{J\,K^{-1}\,mol^{-1}}\),
then the \(\Delta G^\circ\) will be _____ J.
Show Hint
Correct Answer: -13537.6
Solution and Explanation
\(\Delta H^\circ = \Delta U^\circ + \Delta n_g RT = -20000 + (-1)(8.314)(298) = -20000 - 2477.6 = -22477.6\) J.
\(T\Delta S^\circ = 298 \times (-30) = -8940\) J.
\(\Delta G^\circ = \Delta H^\circ - T\Delta S^\circ = -22477.6 + 8940 = -13537.6\) J, i.e. about \(-13538\) J.
Answer: -13537.6 (accepted range -13540 to -13537)
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