(i) A's average number of points = \(\frac{14 + 16 + 10 + 10 }{4}\) = \(\frac{50}{4}\) = 12.5
(ii) To find the mean number of points per game for C, we will divide the total points by 3 because C played 3 games.
(iii) Mean of B's score = \(\frac{0 + 8 + 6 + 4 }{4}\) = \(\frac{18}{4}\) = 4.5
(iv) The best performer will have the greatest average of all. Now we can observe that the average of A is 12.5 which is more than that of B and C. Therefore, A is the best performer among these three.


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |



| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |
