We need to calculate the number of distinct seating arrangements of five people: P, Q, R, S, and T, with the following conditions:
1. Q and R are separated by one person.
2. S should not be seated adjacent to Q.
Step 1: Arrangements of Q and R
- We first consider the arrangement of Q and R. According to the problem, Q and R must be separated by exactly one person.
- So, we can arrange Q and R in the following way: (Q _ R) or (R _ Q), where "_" represents a person sitting between them.
- There are 2 possible arrangements for Q and R.
Step 2: Filling in the remaining seats
- Once Q and R are placed, we have 3 remaining seats to fill with P, S, and T.
- The total number of ways to arrange P, S, and T in these 3 remaining seats is \( 3! = 6 \).
Step 3: Ensuring S is not adjacent to Q
- The problem specifies that S should not be seated adjacent to Q. This restriction must be taken into account.
- Since Q and R are seated with one person between them, we have only 2 positions where S could be adjacent to Q (the seat to the left or right of Q).
- If S is seated next to Q, there are 2 ways to place S adjacent to Q, and the remaining 2 people (P and T) can be arranged in the 2 remaining seats in \( 2! = 2 \) ways.
Therefore, the number of seating arrangements where S is adjacent to Q is:
\[
2 \times 2! = 4
\]
Step 4: Subtracting the invalid arrangements
The total number of unrestricted seating arrangements is:
\[
2 \times 3! = 12
\]
However, we need to exclude the 4 arrangements where S is adjacent to Q. So, the total number of valid arrangements is:
\[
12 - 4 = 8
\]
Thus, the total number of distinct seating arrangements is 16.
Final Answer: (D)