Question

Find the zeroes of the polynomial $2x^2 - 6$.

Hint:

For equations of type $ax^2 - b = 0$:
Move constant term to RHS.
Divide by coefficient of $x^2$.
Take square root.
Always include both $+$ and $-$ roots.

Answer 1

Concept: Zeroes of a polynomial are values of $x$ that make it equal to zero. Step 1: Set the polynomial equal to zero \[ 2x^2 - 6 = 0 \] Step 2: Solve for $x$ \[ 2x^2 = 6 \] \[ x^2 = 3 \] Step 3: Take square root \[ x = \pm \sqrt{3} \] Final Answer: \[ \boxed{x = \pm \sqrt{3}} \]