Question:
Find the product formed for the given reaction.
\[
C_6H_5CHO + H_3C-CH_2CHO \xrightarrow{\text{Dil. NaOH/Δ}} \text{Product}
\]
Find the product formed for the given reaction.
\[ C_6H_5CHO + H_3C-CH_2CHO \xrightarrow{\text{Dil. NaOH/Δ}} \text{Product} \]
\[ C_6H_5CHO + H_3C-CH_2CHO \xrightarrow{\text{Dil. NaOH/Δ}} \text{Product} \]
Show Hint
Aldol condensation of aldehydes, especially under basic conditions, often leads to the formation of β, β-unsaturated aldehydes or ketones. In this case, it forms cinnamaldehyde.
Updated On: Jan 5, 2026
- C\(_2\)H\(_5\)-CH=CH-CHO
- C\(_6\)H\(_5\)-CH\(_2\)CH\(_2\)CHO
- C\(_6\)H\(_5\)-CH\(_2\)-C\(_2\)CHO
- C\(_6\)H\(_5\)-CH=CH-CHO
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The reaction involves the condensation of two aldehydes (benzaldehyde and butanal), where the aldehyde group of one reacts with the CH\(_2\) group of the other in the presence of a dilute NaOH solution and heat. This forms a β, β-unsaturated aldehyde. The product is cinnamaldehyde, which has the structure \( C_6H_5-CH=CH-CHO \). Thus, the correct product is option (D).
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