Question

Find the maximum gain of a \(\frac{\lambda}{2}\) wire dipole operating at 30 MHz?

• A. \(1\)
• B. \(1.64\)
• C. \(10.23\)
• D. \(30.33\)

Hint:

Important antenna gains: \[ \text{Isotropic antenna}=1 \] \[ \text{Half-wave dipole}=1.64 \] \[ \text{Half-wave dipole}=2.15~dB \]

Answer 1

The Correct Option is B

Concept: A half-wave dipole antenna is one of the most important practical antennas. Its standard directivity and gain are well-known quantities. The maximum power gain of a half-wave dipole is \[ G=1.64 \] or \[ G_{dB}=2.15~dB \]

Step 1: Recall the standard gain value.
For a half-wave dipole, \[ G=1.64 \]

Step 2: Observe that operating frequency does not change the normalized gain.
The frequency determines physical dimensions but not the normalized gain value. Therefore, \[ G=1.64 \]

Step 3: Final Answer.
\[ \boxed{1.64} \] Hence, \[ \boxed{\text{Correct Option (B)}} \]