Find the kinetic energy of the fastest emitted electron if an ultraviolet ray of 6.2 falls on the aluminum surface, the work function given is 4.2 eV
Solution and Explanation
Kinetic Energy = Energy of Incident Photon - Work Function
Given:
The energy of Incident Photon = 6.2 eV
Work Function of Aluminum = 4.2 eV
Substituting these values into the equation, we have:
Kinetic Energy = 6.2 eV - 4.2 eV
Calculating the difference, we get:
Kinetic Energy = 2.0 eV
Therefore, the kinetic energy of the fastest emitted electron is 2.0 electron volts (eV).
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