Question:

Find the isentropic compressibility of an ideal gas with an adiabatic index of \(1.4\) at a pressure of \(1\) atm.

Show Hint

For an ideal gas, \[ \boxed{ \beta_s=\frac{1}{\gamma P} } \] where \(\beta_s\) is the isentropic compressibility.
Updated On: Jul 14, 2026
  • \(\dfrac{1}{1.4}\ \text{atm}^{-1}\)
  • \(1.4\ \text{atm}^{-1}\)
  • \(1\ \text{atm}^{-1}\)
  • \(0.4\ \text{atm}^{-1}\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Recall the formula for isentropic compressibility. The isentropic compressibility of an ideal gas is \[ \boxed{ \beta_s=\frac{1}{\gamma P}, } \] where
• \(\gamma\) = adiabatic index,
• \(P\) = pressure.

Step 2:
Substitute the given values. Given, \[ \gamma=1.4, \] \[ P=1\ \text{atm}. \] Hence, \[ \beta_s = \frac{1}{1.4\times1} = \frac{1}{1.4}\ \text{atm}^{-1}. \] Therefore, \[ \boxed{\frac{1}{1.4}\ \text{atm}^{-1}} \] is the correct answer. Thus, \[ \boxed{(A)} \] is the correct answer.
Was this answer helpful?
0
0