Step 1: Find the first derivative of the function.
The first derivative of the function \( f(x) \) is:
\[
f'(x) = \frac{d}{dx}(x^2 - 4x + 6) = 2x - 4
\]
Step 2: Find when the derivative is negative.
For the function to be decreasing, we need \( f'(x) < 0 \). So, solve:
\[
2x - 4 < 0
\]
\[
2x < 4
\]
\[
x < 2
\]
Step 3: Conclusion.
The function \( f(x) = x^2 - 4x + 6 \) is decreasing for \( x < 2 \).
If \( y = \sqrt{e^x} \), \( x > 0 \), then \( \frac{dy}{dx} = \underline{\hspace{2cm}} \)