Substituting n = 20, we obtain
a20 = 20\(\frac{(20-2)}{20+3}\)
= 20\(\frac{(18)}{23}\)
= \(\frac{360}{23}\)
\(f(x) = \begin{cases} x^2, & \quad 0≤x≤3\\ 3x, & \quad 3≤x≤10 \end{cases}\)
The relation g is defined by
\(g(x) = \begin{cases} x^2, & \quad 0≤x≤2\\ 3x, & \quad 2≤x≤10 \end{cases}\)
Show that f is a function and g is not a function.