Find the coordinates of the focus, the axis of the parabola, the equation of directrix, and the length of the latus rectum for \(y^2 = 12x\).
The given equation is \(y^2= 12x. \)
Here, the coefficient of \(x\) is positive.
Hence, the parabola opens towards the right.
On comparing this equation with \(y^2 = 4ax\) , we obtain
\(4a= 12\)
\(⇒ a = 3\)\(\)
∴Coordinates of the focus \(= (a, 0) = (3, 0)\)
Since the given equation involves \(y^2 \), the axis of the parabola is the x-axis.
Equation of direcctrix ,\( x= -a \)
i.e., \(x = - 3\)
\(⇒ x+ 3 = 0 \)
Length of latus rectum : \( 4a= 4*3\) \(=12\)\(\) (Ans.)
\(f(x) = \begin{cases} x^2, & \quad 0≤x≤3\\ 3x, & \quad 3≤x≤10 \end{cases}\)
The relation g is defined by
\(g(x) = \begin{cases} x^2, & \quad 0≤x≤2\\ 3x, & \quad 2≤x≤10 \end{cases}\)
Show that f is a function and g is not a function.
Parabola is defined as the locus of points equidistant from a fixed point (called focus) and a fixed-line (called directrix).

=> MP2 = PS2
=> MP2 = PS2
So, (b + y)2 = (y - b)2 + x2