Question

Find the alkene which gives 2 mol of acetone by ozonolysis.

Hint:

Ozonolysis of alkenes leads to cleavage of the double bond and the formation of carbonyl compounds. The structure of the alkene determines the products formed.

Answer 1

Step 1: Understand the reaction.
Ozonolysis is a reaction in which an alkene undergoes cleavage in the presence of ozone (O\(_3\)) to form two carbonyl compounds. The type of products formed depends on the structure of the alkene. For ozonolysis of an alkene to produce 2 moles of acetone, the alkene must have a structure that leads to the formation of acetone (CH\(_3\)COCH\(_3\)) upon cleavage.
Step 2: Identify the alkene.
The ozonolysis of the following alkene: \[ \text{CH}_3\text{CH} = \text{CH}_2 \] (propen) would produce acetone as one of the products. In this case, the reaction occurs as follows: \[ \text{CH}_3\text{CH} = \text{CH}_2 \xrightarrow{\text{O}_3} 2 \, \text{CH}_3\text{COCH}_3 \] The double bond in propene breaks, and two molecules of acetone (CH\(_3\)COCH\(_3\)) are produced.
Step 3: Conclusion.
Thus, the alkene that gives 2 moles of acetone by ozonolysis is: \[ \boxed{\text{Propene (CH}_3\text{CH} = \text{CH}_2\text{)}} \]