Common ratio, r = 2
Let a be the first term of the G.P.
∴ a8 = ar 8–1 = ar7
⇒ ar7 = 192
a(2) 7 = 192
a(2) 7 = (2)6 (3)
⇒a = (2)6 × \(\frac{3}{(2)}7=\frac{3}{2}\)
∴ a12 = ar12 - 1 = \((\frac{3}{2})\)(2)11 = (3)(2)10 = 3072
\(f(x) = \begin{cases} x^2, & \quad 0≤x≤3\\ 3x, & \quad 3≤x≤10 \end{cases}\)
The relation g is defined by
\(g(x) = \begin{cases} x^2, & \quad 0≤x≤2\\ 3x, & \quad 2≤x≤10 \end{cases}\)
Show that f is a function and g is not a function.