(i) \(\frac{7}{3}\) ÷ 2 = \(\frac{7}{3}\) × \(\frac{1}{2}\) = \(\frac{7}{6}\)
(ii) \(\frac{4}{9}\) ÷ 5 = \(\frac{4}{9}\)× \(\frac{1}{5}\) = \(\frac{4}{45}\)
(iii) \(\frac{6}{13}\) ÷ 7 = \(\frac{6}{13}\) × \(\frac{1}{7}\)= \(\frac{6}{91}\)
(iv) 4 \(\frac{1}{3}\) ÷ 3 = \(\frac{13}{3}\) ÷ 3 = \(\frac{13}{3}\) × \(\frac{1}{3}\) = \(\frac{13}{9}\)
(v) 3 \(\frac{1}{2}\) ÷ 4 = \(\frac{7}{2}\) ÷ 4 = \(\frac{7}{2}\) × \(\frac{1}{4}\) =\(\frac{7}{8}\)
(vi) 4 \(\frac{3}{7}\) ÷ 7 = \(\frac{31}{7}\) × \(\frac{1}{7}\)= \(\frac{31}{49}\)


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |



| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |
