(i) 0.4 ÷ 2 = \(\frac{4}{10}\) ÷ 2 = \(\frac{4}{10}\)× \(\frac{1}{2}\)= \(\frac{2}{10}\) = 0.2
(ii) 0.35 ÷ 5 = \(\frac{35}{100}\) ÷ 5 = \(\frac{35}{100}\) × \(\frac{1}{5}\) = \(\frac{7}{100}\)= 0.07
(iii) 2.48 ÷ 4 = \(\frac{248}{100}\) ÷ 4 = \(\frac{248}{100}\) × \(\frac{1}{4}\) = \(\frac{62}{100}\) = 0.62
(iv) 65.4 ÷ 6 = \(\frac{654}{10}\) ÷ 6 = \(\frac{654}{10}\) × \(\frac{1}{6}\)= \(\frac{109}{10}\) = 10.9
(v) 651.2 ÷ 4 = \(\frac{6512}{10}\) × \(\frac{1}{4}\) = \(\frac{1628}{10}\) = 162.8
(vi) 14.49 ÷ 7 = \(\frac{1449}{100}\) ÷ 7 = \(\frac{1449}{100}\) ×\(\frac{1}{7}\) = \(\frac{207}{100}\) = 2.07
(vii) 3.96 ÷ 4 = \(\frac{396}{100}\) ÷ 4 = \(\frac{396}{100}\)× \(\frac{1}{4}\) = \(\frac{99}{100}\) = 0.99
(viii) 0.80 ÷ 5 = \(\frac{80}{100}\) ÷ 5 = \(\frac{80}{100}\) × \(\frac{1}{5}\) = \(\frac{16}{100}\) = 0.16


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |



| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |
