Find all points of discontinuity of f,where f is defined by
\[f(x) = \begin{cases} \frac {x}{|x|}, & \quad \text{if } x \text{<0}\\ -1, & \quad \text{if } x {\geq 0} \end{cases}\]\(f(x) = \begin{cases} \frac {x}{|x|}, & \quad \text{if } x \text{<0}\\ -1, & \quad \text{if } x {\geq 0} \end{cases}\)
It is known that, x<0\(\implies\)|x| = -x
Therefore, the given function can be rewritten as
\(f(x) = \begin{cases} \frac {x}{|x|}=\frac {x}{-x}=-1, & \quad \text{if } x \text{<0}\\ -1, & \quad \text{if } x {\geq 0} \end{cases}\)
\(\implies\)f(x) = -1 for all x∈R
Let c be a point on the real number.Then, \(\lim\limits_{x \to c}\) f(x) = \(\lim\limits_{x \to c}\) (-1) = -1
Also, f(c) = -1 = \(\lim\limits_{x \to c}\) f(x)
Therefore ,the given function is a continuous function.
Hence, the given function has no point of discontinuity.
Sports car racing is a form of motorsport which uses sports car prototypes. The competition is held on special tracks designed in various shapes. The equation of one such track is given as 
(i) Find \(f'(x)\) for \(0<x>3\).
(ii) Find \(f'(4)\).
(iii)(a) Test for continuity of \(f(x)\) at \(x=3\).
OR
(iii)(b) Test for differentiability of \(f(x)\) at \(x=3\).
Let $\alpha,\beta\in\mathbb{R}$ be such that the function \[ f(x)= \begin{cases} 2\alpha(x^2-2)+2\beta x, & x<1 \\ (\alpha+3)x+(\alpha-\beta), & x\ge1 \end{cases} \] is differentiable at all $x\in\mathbb{R}$. Then $34(\alpha+\beta)$ is equal to}
A function is said to be continuous at a point x = a, if
limx→a
f(x) Exists, and
limx→a
f(x) = f(a)
It implies that if the left hand limit (L.H.L), right hand limit (R.H.L) and the value of the function at x=a exists and these parameters are equal to each other, then the function f is said to be continuous at x=a.
If the function is undefined or does not exist, then we say that the function is discontinuous.
Conditions for continuity of a function: For any function to be continuous, it must meet the following conditions: