
If the initial pressure of a gas 0.03 atm, the mass of the gas absorbed per gram of the adsorbent is ____× 10–2g
The correct answer is 12
Given that log K = intercept = 0.602 = log 4
∴ K = 4
Slope \(=\frac{1}{n}=1\) and
initial pressure = 0.03 atm
\(\frac{x}{m}=K(p)^{\frac{1}{n}} \)
= 4 × 0.03 = 0.12 = 12 × 10–2
∴ mass of gas absorbed per gm of adsorbent = 12 × 10–2 g
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
One mole of an ideal monoatomic gas is subjected to changes as shown in the graph The magnitude of the work done (by the system or on the system) is _______ J (nearest integer)
Given : \(\log 2=0.3 \ln 10=2.3\)
In figure, a straight line is given for Freundrich Adsorption\((y=3 x+2505)\) The value of \(\frac{1}{ n }\)and\(\log K\)are respectively
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Heinrich Kayser, the German physicist was the first to coin the term adsorption. Adsorption can be explained as a surface phenomenon where particles remain attached on the top of a material. Generally, it comprises the molecules, atoms, liquid, solid in a dissolved stage, even the ions of a gas that are attached to the surface. Much to our surprise, the consequence of surface energy i.e. adsorption is present in biological, physical, chemical, and natural systems and are used in many industrial applications.
