fe3+ is reduced to fe2+ by using
fe3+ is reduced to fe2+ by using
H2O2 in the presence of NaOH
Na2O2 in water
H2O2 in the presence of H2SO4
Na2O2 in the presence of H2SO4
The Correct Option is C, D
Solution and Explanation
H2O2 in the presence of H2SO4
Na2O2 in the presence of H2SO4
By using H₂O₂ in the presence of NaOH. In this H₂O₂ will act as a reducing agent and OH ion will act as a base. The balanced reaction is as follows:
2 Fe³⁺ + 2 H₂O₂ + 2 OH⁻ → 2 Fe²⁺ + 2H₂O + O₂
Another way is by using, Na₂O₂ in water. In the reaction, sodium peroxide will act as a strong oxidizing agent and therefore donate the oxygen atom. Water will provide the medium. The reaction for the same is as follows:
2Fe³⁺ + Na₂O₂ + 2H₂O → 2 Fe²⁺ + 2NaOH + H₂O₂
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
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Top JEE Main Redox reactions Questions
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\(a \, \text{Cl}_2(g) + b \, \text{OH}^-(\text{aq}) \rightarrow c \, \text{ClO}^-(\text{aq}) + d \, \text{Cl}^-(\text{aq}) + e \, \text{H}_2\text{O}(\text{l})\)
The values of \( a \), \( b \), \( c \), and \( d \) in a balanced redox reaction are respectively: - In alkaline medium, \( \text{MnO}_4^- \) oxidizes \( \text{I}^- \) to:
- In acidic medium, \( K_2Cr_2O_7 \) shows oxidizing action as represented in the half-reaction: \(Cr_2O_7^{2-} + XH^+ + Ye^- \rightarrow 2A + ZH_2O\)
\( X \), \( Y \), \( Z \), and \( A \) are respectively:
Top JEE Main Questions
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- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
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