Question:
FAR stands for
FAR stands for
Show Hint
FAR is a building-regulation ratio of built-up floor area to plot area.
Updated On: Nov 12, 2026
- Facade Area Ratio
- Floor Area Ratio
- Fire Accessible Ramp
- Fire Arch Ratio
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
In building regulations, FAR means Floor Area Ratio (also called FSI), the ratio of the total covered floor area of all floors of a building to the area of the plot.
The other expansions are not standard terms.
Answer: (2) Floor Area Ratio
The other expansions are not standard terms.
Answer: (2) Floor Area Ratio
Was this answer helpful?
0
0
Top JEE Main Aptitude Questions
- Why is a beam used in buildings?
- Where does the President of the USA live?
- Whose residence is Downing street?
- Where is Notre Dame Cathedral?
- Who built Shalimar Bagh?
View More Questions
Top JEE Main Architecture Awareness Questions
- 'LEED' stands for :
- Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : Green buildings have a lower life cycle cost than conventional buildings.
Reason R : Green buildings require less maintenance and have lower energy and water consumption.
In the light of the above statements, choose the most appropriate answer from the options given below : - Match List I with List II
Choose the correct answer from the options given below: - Identify the building material primarily used for cladding in Lotus Temple :
- Which of the following is a shell structure?
View More Questions
Top JEE Main Questions
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
View More Questions