Question:

Facultative anaerobes produce more ATP per mole of glucose under aerobic conditions because

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ATP production: \[ \boxed{ \begin{aligned} \text{Aerobic respiration} &\rightarrow \text{Oxidative phosphorylation} \rightarrow \text{High ATP}\\ \text{Fermentation} &\rightarrow \text{Low ATP} \end{aligned} } \]
Updated On: Jul 23, 2026
  • Fermentation is faster
  • Glycolysis is inhibited
  • Oxidative phosphorylation operates
  • NADH is not formed
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The Correct Option is C

Solution and Explanation

Under aerobic conditions, facultative anaerobes use oxygen as the terminal electron acceptor. This allows oxidative phosphorylation to occur, generating much more ATP than fermentation. Hence, \[ \boxed{\text{Oxidative phosphorylation operates}} \] is the correct answer. Therefore, \[ \boxed{(C)} \]
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