The given integral can be evaluated using logarithmic properties and integration techniques.
We rewrite the logarithmic term: \[ \log \left( \frac{1}{x - 1} \right) = - \log(x - 1) \] Thus, the integral becomes: \[ \int_0^1 \log \left( \frac{1}{x - 1} \right) dx = - \int_0^1 \log(x - 1) \, dx \] The integral of \( \log(x - 1) \) from 0 to 1 gives 0, as the value of the integral at these limits cancels out due to symmetry.
Thus, the final answer is 0.