Question:

\(\displaystyle \int \frac{dx}{25-x^2}=\)

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Remember the standard formula \(\int\frac{dx}{a^2-x^2}=\frac{1}{2a}\log\left|\frac{a+x}{a-x}\right|+c\).
  • \(\frac{1}{5}\log\left|\frac{x-5}{x+5}\right|+c\)
  • \(\frac{1}{5}\log\left|\frac{x+5}{x-5}\right|+c\)
  • \(\frac{1}{10}\log\left|\frac{5+x}{5-x}\right|+c\)
  • \(\frac{1}{10}\log\left|\frac{5-x}{5+x}\right|+c\)
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The Correct Option is C

Solution and Explanation

We need to evaluate: \[ \int \frac{dx}{25-x^2}. \] Write \[ 25-x^2=5^2-x^2. \] We know the standard formula: \[ \int \frac{dx}{a^2-x^2} = \frac{1}{2a}\log\left|\frac{a+x}{a-x}\right|+c. \] Here, \[ a=5. \] Therefore, \[ \int \frac{dx}{25-x^2} = \frac{1}{2(5)}\log\left|\frac{5+x}{5-x}\right|+c. \] \[ = \frac{1}{10}\log\left|\frac{5+x}{5-x}\right|+c. \] Hence, \[ \int \frac{dx}{25-x^2} = \frac{1}{10}\log\left|\frac{5+x}{5-x}\right|+c. \]
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