Discuss the continuity of the following functions.
(a) f(x)=sinx+cosx
(b) f(x)=sinx−cosx
(c) f(x)=sinx\(\times\)cosx
It is known that if g and h are two continuous functions, then
g+h,g-h and g.h are also continuous.
It has to proved first that g(x)=sinx and h(x)=cos x are continuous functions.
Let g(x)=sinx It is evident that g(x)=sinx is defined for every real number.
Let c be a real number. Put x=c+h
If x\(\rightarrow\)c,then h\(\rightarrow\)0
g(c)=sinc
\(\lim_{x\rightarrow c}g(x)\)=\(\lim_{x\rightarrow c}sin\,x\)
=\(\lim_{h\rightarrow 0}sin(c+h)\)
=\(\lim_{h\rightarrow 0}\)[sin c cos h+cos c sin h]
=sin c cos 0+cos c sin 0
=sin c+0=sin c
∴\(\lim_{x\rightarrow c}g(x)\)=\(g(c)\)
Therefore, g is a continuous function.
Let h(x)=cos x It is evident that h(x)=cosx is defined for every real number.
Let c be a real number. Put x=c+h
If x\(\rightarrow\)c, then h\(\rightarrow\)0
h(c)=cosc
\(\lim_{x\rightarrow c}\)h(x)=\(\lim_{x\rightarrow c}\) cos x
=\(\lim_{h\rightarrow 0}\)cos(c+h)
=\(\lim_{h\rightarrow 0}\)[cosccosh-sincsinh]
=\(\lim_{h\rightarrow 0}\)cos c cos h-\(\lim_{h\rightarrow 0}\) sin c sin h
=cos c cos 0-sin csin 0
=cos c\(\times\)1-sin c\(\times\)0
=cos c
∴\(\lim_{x\rightarrow c}\)h(x)=h(c)
Therefore, h is a continuous function.
Therefore, it can be concluded that
(a)f(x)=g(x)+h(x)=sinx+cosx is a continuous function
(b)f(x)=g(x)-h(x)=sinx−cosx is a continuous function
(c)f(x)=g(x)×h(x)=sinx×cosx is a continuous function
Sports car racing is a form of motorsport which uses sports car prototypes. The competition is held on special tracks designed in various shapes. The equation of one such track is given as 
(i) Find \(f'(x)\) for \(0<x>3\).
(ii) Find \(f'(4)\).
(iii)(a) Test for continuity of \(f(x)\) at \(x=3\).
OR
(iii)(b) Test for differentiability of \(f(x)\) at \(x=3\).
Let $\alpha,\beta\in\mathbb{R}$ be such that the function \[ f(x)= \begin{cases} 2\alpha(x^2-2)+2\beta x, & x<1 \\ (\alpha+3)x+(\alpha-\beta), & x\ge1 \end{cases} \] is differentiable at all $x\in\mathbb{R}$. Then $34(\alpha+\beta)$ is equal to}