Question:

Directions for Questions 97 to 101: A company launches eight products, Q, R, S, T, V, W, Y and Z, in one of the four metros of India. The products are launched one after another over a period of six months in 2006. The order of launch follows these conditions:

  • V is launched before both Y and Q.
  • Q gets launched after Z.
  • T gets launched before V but after R.
  • S gets launched after V.
  • R gets launched before W.

Q101. If V gets launched before Z does, then which one of the following COULD be true?

Show Hint

Adding V before Z stretches the chain to R, T, V, Z, Q in strict order; work out the earliest and latest position each can sit in.
Updated On: Jul 13, 2026
  • R is the second product to be launched.
  • T is the fourth product to be launched.
  • Q is the fourth product to be launched.
  • Z is the sixth product to be launched.
Show Solution
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The Correct Option is D

Solution and Explanation

Step 1: Extend the base chain with the new condition.
The base rules already give R before T before V, and V before Q, Y and S. Z was previously free except for Z before Q.
Now we are told V launches before Z as well. Combined with the base rule Z before Q, this stretches the chain to R before T before V before Z before Q, a strict order of five distinct products.

Step 2: See what this forces for R.
Earlier, Z was the one product that could sit ahead of R. But now Z is placed after V, which is after T, which is after R, so Z is always after R in this scenario. That removes R's only possible predecessor, so R must be launched first.

Step 3: Test each option.
Option 1 says R is the second product, but we just showed R must be first. Impossible.
Option 2 says T is the fourth product. Only W has no rule tying it ahead of T (since Y, S, Z, Q all come after V, which is after T), so at most one product (W) can slot in between R and T. That limits T to at most third position (R, W, T at 1, 2, 3). T can never reach fourth. Impossible.
Option 3 says Q is the fourth product. The chain R before T before V before Z before Q needs five increasing positions for five different products, so Q's earliest possible position is fifth. Q can never be fourth. Impossible.
Option 4 says V is the fifth product. After V, three more chain members (Z, then Q) plus Y and S all need positions after V, that is four products needing room after position 5, but only three slots (6, 7, 8) remain. Impossible.
Option 5 says Z is the sixth product. Try R, T, V, W, Y, Z, S, Q: R before T before V holds (1,2,3), V before Y holds (3 before 5), V before Z holds (3 before 6, the new condition), Z before Q holds (6 before 8), V before S holds (3 before 7), R before W holds (1 before 4). Every rule is satisfied, so this is a genuine valid order with Z sixth.

Final Answer:
Only "Z is the sixth product to be launched" survives every check.
\[ \boxed{\text{"Z is the sixth product to be launched."}} \]
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