Question:

Directions for Questions 102 to 107: A retail electronics showroom chain has six new mobile phone models, T, V, W, X, Y and Z, each equipped with at least one of three options: digital camera, music player and office document viewer. No phone has any other option. The following conditions apply:

  • V features both a digital camera and an office document viewer.
  • W has a digital camera and a music player.
  • W and Y have no options in common.
  • X has more options than W.
  • V and Z have exactly one option in common.
  • T has fewer options than Z.

Q104. If Z has no option in common with T but has at least one option in common with every other mobile phone, then which one of the following must be false?

Show Hint

Test both of Z's possible option sets against Y first; only one avoids a zero-overlap conflict. Then see what is left over for T.
Updated On: Jul 13, 2026
  • T has digital camera.
  • Z has document viewer.
  • Exactly four of the six mobile phones have digital camera.
  • Exactly four of the six mobile phones have music player.
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The Correct Option is D

Solution and Explanation

Step 1: Recall Z's two possible identities.
From the base rules, Z is either {camera, music} or {document viewer, music}, and it always shares exactly one option with V = {camera, document viewer}.

Step 2: Apply "Z shares at least one option with every other phone."
Check Z = {camera, music} against Y = {document viewer}: there is no overlap at all, which breaks the new rule that Z must share something with every other phone. So Z cannot be {camera, music} here.
Check Z = {document viewer, music} against Y = {document viewer}: they share the document viewer, which works. Against W = {camera, music}: they share music, which works. Against X = {camera, music, document viewer}: they share both music and document viewer, which works. Against V: they share the document viewer, exactly one option, consistent with the base rule. So Z = {document viewer, music} is the only identity that survives.

Step 3: Apply "Z shares nothing with T."
T has exactly one option. Since Z = {document viewer, music}, T cannot be document viewer or music, or it would overlap with Z. That leaves only one choice: T = {camera}.

Step 4: Compute the final option set for all six phones and count each option.
V = {camera, document viewer}, W = {camera, music}, X = {camera, music, document viewer}, Y = {document viewer}, Z = {document viewer, music}, T = {camera}.
Camera holders: V, W, X, T, that is 4 phones.
Music holders: W, X, Z, that is 3 phones.
Document viewer holders: V, X, Y, Z, that is 4 phones.

Step 5: Check each option.
Option 1, T has a digital camera: true, since T = {camera}.
Option 2, Z has a document viewer: true, since Z = {document viewer, music}.
Option 3, exactly four have a digital camera: true, matches the count above.
Exactly four have a document viewer: true, matches the count above (this was original option 4, dropped in the fold).
Option 4 (originally option 5), exactly four have a music player: false, since only 3 phones (W, X, Z) carry music, not 4.

Final Answer:
The extra condition pins every phone down to one exact answer, and checking the counts shows the music-player count is 3, not 4.
\[ \boxed{\text{"Exactly four of the six mobile phones have music player" must be false.}} \]
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