Question:

Dichromate ion is treated with base, the oxidation number of Cr in the product formed is ___________.

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In base, orange \(\mathrm{Cr_2O_7^{2-}}\) converts to yellow \(\mathrm{CrO_4^{2-}}\) without any redox change.
Updated On: Nov 4, 2026
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Correct Answer: 6

Solution and Explanation

With base, dichromate changes to chromate: \(\mathrm{Cr_2O_7^{2-} + 2OH^- \to 2CrO_4^{2-} + H_2O}\).
Oxidation number of Cr in \(\mathrm{CrO_4^{2-}}\): \(x + 4(-2) = -2 \Rightarrow x = +6\).
This is not a redox reaction, so Cr stays +6.
Answer: 6
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