Question:
Determine the moment of inertia of a rectangular beam section with a width of 300 mm and height of 500 mm about its neutral axis.
Determine the moment of inertia of a rectangular beam section with a width of 300 mm and height of 500 mm about its neutral axis.
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The formula for the moment of inertia of a rectangle is $\frac{1}{12} b h^3$ where $b$ is the base and $h$ is the height.
Updated On: Jun 17, 2025
- $1.25 \times 10^7$ mm\(^4\)
- $2.5 \times 10^7$ mm\(^4\)
- $3.75 \times 10^7$ mm\(^4\)
- $4.5 \times 10^7$ mm\(^4\)
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The Correct Option is A
Solution and Explanation
The moment of inertia $I$ for a rectangle about its neutral axis is given by: \[ I = \frac{1}{12} b h^3 \] Substituting the values: \[ I = \frac{1}{12} \times 300 \times (500)^3 = 1.25 \times 10^7 \, \text{mm}^4 \]
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