\( \Delta \)G\( ^\circ \) vs T plot for the formation of MgO, involving reaction
2Mg + O2 \( \to \) 2MgO, will look like :
\( \Delta \)G\( ^\circ \) vs T plot for the formation of MgO, involving reaction
2Mg + O2 \( \to \) 2MgO, will look like :
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The Correct Option is A
Solution and Explanation
Step 2: At the boiling point of Mg (about 1363 K) Mg changes from liquid to gas; the reaction then consumes even more gas (2Mg(g) + O2(g) \(\to\) 2MgO(s)), \(\Delta S^\circ\) becomes more negative and the slope becomes steeper.
Step 3: The graph is therefore a rising line that bends upward into a steeper rising line at a higher temperature.
Answer: (A) the first graph (rising line with a sharper rise after the bend)
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