A = {x: x R and x satisfies \(x^2- 8x + 12 = 0\)}
2 and 6 are the only solutions of \(x^2- 8x + 12 = 0.\)
∴ A = {2, 6}
B = {2, 4, 6}, C = {2, 4, 6, 8 …}, D = {6}
\(∴ D ⊂ A ⊂ B ⊂ C\)
Hence, \(A ⊂ B, A ⊂ C, B ⊂ C, D ⊂ A, D ⊂ B, D ⊂ C\)
\(f(x) = \begin{cases} x^2, & \quad 0≤x≤3\\ 3x, & \quad 3≤x≤10 \end{cases}\)
The relation g is defined by
\(g(x) = \begin{cases} x^2, & \quad 0≤x≤2\\ 3x, & \quad 2≤x≤10 \end{cases}\)
Show that f is a function and g is not a function.
Some important operations on sets include union, intersection, difference, and the complement of a set, a brief explanation of operations on sets is as follows:
1. Union of Sets:
2. Intersection of Sets:
3.Set Difference:
4.Set Complement: