Question:

Correct formula of the compound which gives a white precipitate with BaCl2 solution, but not with AgNO3 solution, is :

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BaCl2 gives a white precipitate only with free sulphate; AgNO3 gives a precipitate only with free halide ions. Ligands inside the square brackets do not ionise.
Updated On: Oct 31, 2026
  • [Co(NH3)5Br]SO4
  • [Co(NH3)5SO4]Br
  • [Pt(NH3)4Cl2]Br2
  • [Pt(NH3)4Br2]Cl2
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The Correct Option is A

Solution and Explanation

Step 1: The compound must have free SO42\(-\) (to give white BaSO4 with BaCl2) and no free Cl\(-\)/Br\(-\) (to give no precipitate with AgNO3).
Step 2: [Co(NH3)5Br]SO4 ionises to [Co(NH3)5Br]2+ + SO42\(-\): sulphate is free and bromide is bound, which fits.
Step 3: [Co(NH3)5SO4]Br has free Br\(-\) (gives AgBr) and bound sulphate; the Pt complexes have free Br\(-\) or Cl\(-\) and no sulphate at all.
Answer: (A) [Co(NH3)5Br]SO4
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