Question:
Consider two Ordinary Differential Equations (ODEs) :
\(P:\frac{dy}{dx}=\frac{x^4+3x^2y^2+2y^4}{x^3y}\)
\(Q:\frac{dy}{dx}=\frac{-y^2}{x^2}\)
Which one of the following options is CORRECT ?
Consider two Ordinary Differential Equations (ODEs) :
\(P:\frac{dy}{dx}=\frac{x^4+3x^2y^2+2y^4}{x^3y}\)
\(Q:\frac{dy}{dx}=\frac{-y^2}{x^2}\)
Which one of the following options is CORRECT ?
\(P:\frac{dy}{dx}=\frac{x^4+3x^2y^2+2y^4}{x^3y}\)
\(Q:\frac{dy}{dx}=\frac{-y^2}{x^2}\)
Which one of the following options is CORRECT ?
Updated On: Feb 3, 2026
- P is a homogeneous ODE and Q is an exact ODE.
- P is a homogeneous ODE and Q is not an exact ODE.
- P is a nonhomogeneous ODE and Q is an exact ODE.
- P is a nonhomogeneous ODE and Q is not an exact ODE.
Show Solution
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The Correct Option is B
Solution and Explanation
The correct option is (B) : P is a homogeneous ODE and Q is not an exact ODE..
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