Step 1: Identify the network topology.
The circuit is a symmetric T-section: a \(1\ k\Omega\) resistor in series on the input side, a \(1\ k\Omega\) resistor as the shunt (middle) arm, and a \(1\ k\Omega\) resistor in series on the output side. Call these \(Z_1=Z_3=1000\ \Omega\) (the two series arms) and \(Z_2=1000\ \Omega\) (the shunt arm).
Step 2: Recall the ABCD parameters of a T-network.
For a general T-section with series arms \(Z_1,Z_3\) and shunt arm \(Z_2\),
\[
A=1+\frac{Z_1}{Z_2},\qquad B=Z_1+Z_3+\frac{Z_1Z_3}{Z_2},\qquad C=\frac{1}{Z_2},\qquad D=1+\frac{Z_3}{Z_2}
\]
Step 3: Substitute the resistor values.
\[
A=1+\frac{1000}{1000}=2,\qquad D=1+\frac{1000}{1000}=2
\]
\[
C=\frac{1}{1000}=10^{-3}\ \Omega^{-1}
\]
\[
B=1000+1000+\frac{1000\times1000}{1000}=1000+1000+1000=3000\ \Omega=3\times10^3\ \Omega
\]
Step 4: Analyze the options.
(A) \(A=1/2,\ B=3\times10^3\ \Omega,\ C=10^{-3}\ \Omega^{-1},\ D=1/2\): The \(B\) and \(C\) values match but \(A\) and \(D\) are inverted. Incorrect.
(B) \(A=2,\ B=3\ \Omega,\ C=1\ \Omega^{-1},\ D=2\): \(A\) and \(D\) are right but \(B\) and \(C\) are off by a factor of \(1000\), a common unit slip. Incorrect.
(C) \(A=2,\ B=6\times10^3\ \Omega,\ C=2\times10^{-3}\ \Omega^{-1},\ D=2\): \(B\) and \(C\) are exactly double the correct values. Incorrect.
(D) \(A=2,\ B=3\times10^3\ \Omega,\ C=10^{-3}\ \Omega^{-1},\ D=2\): Matches every computed value. Correct.
Step 5: Final conclusion.
\[
\boxed{A=2,\ B=3\times10^3\ \Omega,\ C=10^{-3}\ \Omega^{-1},\ D=2}
\]