Question:

Consider the reaction :
\(\mathrm{H_2SO_{3(aq)}+Sn^{4+}_{(aq)}+H_2O_{(l)}\rightarrow Sn^{2+}_{(aq)}+HSO^{-}_{4(aq)}+3H^{+}_{(aq)}}\)
Which of the following statements is correct ?

Show Hint

Find which species changes its oxidation number upward.
Updated On: Nov 11, 2026
  • \(\mathrm{Sn^{4+}}\) is the oxidizing agent because it undergoes oxidation
  • \(\mathrm{Sn^{4+}}\) is the reducing agent because it undergoes oxidation
  • \(\mathrm{H_2SO_3}\) is the reducing agent because it undergoes oxidation
  • \(\mathrm{H_2SO_3}\) is the reducing agent because it undergoes reduction
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The Correct Option is C

Solution and Explanation

Sulphur: +4 in H2SO3 goes to +6 in HSO4-, so H2SO3 is oxidised and acts as the reducing agent.
Tin: +4 in Sn4+ goes to +2 in Sn2+, so Sn4+ is reduced and acts as the oxidising agent.
Hence statement (3) is correct.
Answer: (3) \(\mathrm{H_2SO_3}\) is the reducing agent because it undergoes oxidation
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