Question

Consider the reaction
\[ Fe_2O_3 (s) + 3CO (g) \rightleftharpoons 2Fe (l) + 3CO_2 (g) \]
In accordance with Le-Chatlier's principle, which of the following will not disturb the equilibrium?

• A. Removal of \( CO_2 \)
• B. Addition of \( CO \)
• C. Removal of \( CO \)
• D. Addition of \( Fe_2O_3 \)

Hint:

In equilibrium problems, only gases and solutes affect equilibriumPure solids and liquids do not change equilibrium position.

Answer 1

The Correct Option is D

Step 1: Understand Le-Chatelier's principle.
According to Le-Chatelier's principle, a system at equilibrium shifts in a direction that counteracts any imposed change.

Step 2: Identify phases involved.
In the given reaction:
\( Fe_2O_3 \) is a solid, \( CO \) and \( CO_2 \) are gases, and \( Fe \) is a liquid.
Only gaseous species affect equilibrium when concentration changes occur.

Step 3: Analyze each option.
(A) Removal of \( CO_2 \): Decreases product concentration, equilibrium shifts forward.
(B) Addition of \( CO \): Increases reactant concentration, equilibrium shifts forward.
(C) Removal of \( CO \): Decreases reactant concentration, equilibrium shifts backward.
(D) Addition of \( Fe_2O_3 \): Since it is a solid, its concentration does not affect equilibrium.

Step 4: Conclusion.
Addition of a pure solid does not disturb equilibrium.
Therefore:
\[ \boxed{\text{Addition of } Fe_2O_3} \]