Step 1: Understanding the Question:
The question asks for the number of goats received by the youngest son (the fourth son).
Scenario Breakdown:
Let the total wealth of the shepherd be 'W'. The wealth is distributed equally among four sons, so each son's share is W/4.
Eldest Son's Share: The eldest son received sheep worth 20% of the total worth (0.2W) and Rupees 33,750 in cash.
\[ \frac{W}{4} = 0.2W + 33,750 \]
\[ 0.25W - 0.2W = 33,750 \]
\[ 0.05W = 33,750 \]
\[ W = \frac{33,750}{0.05} = 675,000 \]
The total wealth is Rupees 6,75,000. Each son's share is \( \frac{675,000}{4} = \text{Rupees} 1,68,750 \).
Eldest Son's Details: Sheep worth = 0.2 \(\times\) 675,000 = Rupees 1,35,000. Cash = Rupees 33,750. Total = Rupees 1,68,750.
Second Son's Details: The remaining worth after the first son is \( W - \frac{W}{4} = \frac{3W}{4} = 506,250 \). He received goats worth 20% of this remaining worth.
Goats worth = 0.2 \(\times\) 506,250 = Rupees 1,01,250.
Cash = Rupees 67,500.
Total = 1,01,250 + 67,500 = Rupees 1,68,750. (This matches)
Third and Fourth Sons' Details: The remaining worth after the second son is \( 506,250 - 1,68,750 = \text{Rupees}3,37,500 \).
Their total share is \( 2 \times 1,68,750 = \text{Rupees}3,37,500 \), which matches the remaining amount.
The cash for each was Rupees33,750 more than the second son: Rupees 67,500 + Rupees 33,750 = Rupees 1,01,250.
The value of cattle for each son is their total share minus cash: Rupees 1,68,750 - Rupees 1,01,250 = Rupees 67,500.
They received an equal number of sheep (s) and goats (g), so s = g.
\[ s \times 5400 + g \times 1350 = 67,500 \]
\[ g \times (5400 + 1350) = 67,500 \]
\[ g \times 6750 = 67,500 \implies g = 10 \]
So, the third and fourth sons each received 10 sheep and 10 goats.
Step 2: Key Formula or Approach:
Based on our initial breakdown of the scenario, the youngest son received cattle worth Rupees67,500, consisting of an equal number of sheep and goats.
Let 'n' be the number of sheep and also the number of goats.
Value of 1 sheep = Rupees5,400.
Value of 1 goat = Rupees1,350.
\[ n \times (\text{Value of sheep}) + n \times (\text{Value of goat}) = \text{Total Cattle Value} \]
Step 3: Detailed Explanation:
\[ n \times 5,400 + n \times 1,350 = 67,500 \]
\[ n \times (5,400 + 1,350) = 67,500 \]
\[ n \times 6,750 = 67,500 \]
\[ n = \frac{67,500}{6,750} = 10 \]
So, the youngest son received 10 goats (and 10 sheep).
Step 4: Final Answer:
The number of goats the youngest son received was 10.