Consider the last electron of element having atomic number 9 and choose the correct option.
Show Hint
- Sum total nodes = 1
- \( n = 2; l = 0 \)
- Last electron enters 2s subshell
- There are 5 \( e^- \) with \( l = 0 \)
The Correct Option is A
Solution and Explanation
Step 1: Quantum numbers for the last electron:
The electron configuration shows that the last electron is in the \( 2p \) orbital, so:
The principal quantum number \( n = 2 \),
The azimuthal quantum number \( l = 1 \) (since it is a p orbital),
The magnetic quantum number \( m_l \) can range from -1 to +1 (for a p orbital).
Step 2: Calculate the total number of nodes:
The total number of nodes \( N \) is given by: \[ N = n - 1 \] For \( n = 2 \), the total number of nodes is: \[ N = 2 - 1 = 1 \] Conclusion:
The total number of nodes for the last electron is 1, corresponding to option (1).
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