Consider the given figure and choose the correct option:
The given figure represents a typical energy profile diagram for a chemical reaction. It shows the energy of reactants, products, and the activated complex (transition state). Two energy differences are marked:
• E1: Energy difference between the product and the activated complex.
• E2: Energy difference between the reactant and the product.
1. Forward Activation Energy
The forward activation energy is the energy needed to convert reactants into the activated complex. This is the total vertical energy gap from the reactant level to the peak of the curve.
Reactant → Product = E2
Product → Activated complex = E1
So, forward activation energy = E1 + E2
2. Backward Activation Energy
Backward activation energy is the energy required for the reverse reaction (product → activated complex). This is simply the energy gap between product and the activated complex:
Backward activation energy = E1
3. Stability of Reactant vs Product
Stability is inversely related to energy: a species with lower energy is more stable.
In the diagram, the product is at a higher energy level than the reactant. Therefore, the product is less stable and the reactant is more stable.
Conclusion
• Forward activation energy = E1 + E2
• Product is less stable than reactant
These statements match exactly with Option 3.
Correct Answer: Option 3
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

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For reaction \(A \rightarrow P\), rate constant \(k = 1.5 \times 10^3\ s^{-1}\) at \(27^\circ C\). If activation energy for the above reaction is \(60\ kJ\ mol^{-1}\), then the temperature (in \(^{\circ}C\)) at which rate constant \(k = 4.5 \times 10^3\ s^{-1}\) is ______. (Nearest integer) \[ \text{Given: } \log 2 = 0.30,\ \log 3 = 0.48,\ R = 8.3\ J\ K^{-1}\ mol^{-1},\ \ln 10 = 2.3 \]
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)