Step 1: Rewrite functions in exponential form.
We rewrite each function using exponentials to compare growth rates:
\[
f_2 = n^{\log n} = e^{(\log n)^2},
f_3 = n^{\sqrt{n}} = e^{\sqrt{n}\log n},
f_1 = 10^n = e^{n\log 10}.
\]
Step 2: Compare exponents.
\[
(\log n)^2 \ll \sqrt{n}\log n \ll n.
\]
Hence, \( f_2 \) grows slower than \( f_3 \), and \( f_3 \) grows slower than \( f_1 \).
Step 3: Arrange in increasing order.
\[
f_2 < f_3 < f_1.
\]
Consider the following recurrence relation.
\[ T(n) = \begin{cases} T(n/2) + T(2n/5) + 7n, & \text{if } n > 0 \\ 1, & \text{if } n = 0 \end{cases} \] Which one of the following options is correct?