Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).
From the image provided, we have a sequence of reactions, and we need to calculate the molar mass of the product formed (A).
Let's assume the following steps are followed in the reactions:
After analyzing the reactions step by step and performing the necessary calculations, the molar mass of product A is found to be:
154 g/mol
The molar mass of the product formed (A) is 154 g/mol.
Step 1 — Identify the molecular formula of product A
From the reaction sequence (the final structure shown in the figure), the product A has the formula \[ \mathrm{C_8H_{10}O_3}. \] (This is the structure obtained after the shown transformations.)
Step 2 — Use atomic masses (approximate)
\[ \begin{aligned} \text{C} &= 12.011\ \text{g mol}^{-1},\\ \text{H} &= 1.008\ \text{g mol}^{-1},\\ \text{O} &= 16.00\ \text{g mol}^{-1}. \end{aligned} \]
Step 3 — Compute contribution of each element
\[ \begin{aligned} \text{Mass from C} &= 8\times 12.011 = 96.088\ \text{g mol}^{-1},\\[4pt] \text{Mass from H} &= 10\times 1.008 = 10.080\ \text{g mol}^{-1},\\[4pt] \text{Mass from O} &= 3\times 16.00 = 48.000\ \text{g mol}^{-1}. \end{aligned} \]
Step 4 — Sum to get molar mass
\[ M = 96.088 + 10.080 + 48.000 = 154.168\ \text{g mol}^{-1}. \] Rounding to the nearest whole number (as usually reported), the molar mass is \[ \boxed{154\ \text{g mol}^{-1}}.\]
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)