Question:

Consider the following reactions
A \(\rightarrow\) P1 ; B \(\rightarrow\) P2 ; C \(\rightarrow\) P3 ; D \(\rightarrow\) P4,
The order of the above reactions are a, b, c, and d, respectively. The following graph is obtained when log[rate] vs. log[conc.] are plotted

Among the following, the correct sequence for the order of the reactions is :

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For rate = k[conc]n, log rate = log k + n log[conc], so the slope of each line equals the order; compare the slopes in the graph.
Updated On: Nov 5, 2026
  • d \(\gt\) b \(\gt\) a \(\gt\) c
  • d \(\gt\) a \(\gt\) b \(\gt\) c
  • a \(\gt\) b \(\gt\) c \(\gt\) d
  • c \(\gt\) a \(\gt\) b \(\gt\) d
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The Correct Option is A

Solution and Explanation

Rate = k[X]n gives \(\log(\text{rate})=\log k+n\log[\text{conc.}]\). So each line has slope equal to the order of the reaction.
From the graph the steepness of the lines is: D (solid, steepest) > B (dashed, steeper) > A (dashed) > C (solid, shallowest).
Therefore the order sequence is d > b > a > c.
Answer: (1) d > b > a > c
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