Formation of photochemical smog involves the following reaction in which A, B, and C are respectively:
\(\text{NO}_2 \xrightarrow{h\nu} \text{A} + \text{B}\)
\(\text{B} + \text{O}_2 \rightarrow \text{C}\)
\(\text{A} + \text{C} \rightarrow \text{NO}_2 + \text{O}_2\)
Choose the correct answer from the options given below:
NO, O, and O3
N2O and NO
N, O2, and O3
O, NO, and NO3
Step 1: Breakdown of Reactions
Reaction (i): \(\text{NO}_2\) undergoes photodissociation under sunlight:
\[\text{NO}_2 \xrightarrow{h\nu} \text{NO (A)} + \text{O (B)}.\]
Reaction (ii): The oxygen radical (B) reacts with molecular oxygen to form ozone:
\[\text{O (B)} + \text{O}_2 \rightarrow \text{O}_3 (\text{C}).\]
Reaction (iii) \(\text{NO (A)}\) reacts with ozone to regenerate \(\text{NO}_2\) and molecular oxygen:
\[\text{NO (A)} + \text{O}_3 (\text{C}) \rightarrow \text{NO}_2 + \text{O}_2.\]
Step 2: Identify A, B, and C
From the reactions:
\(\text{A} = \text{NO}\) (Nitric oxide),
\(\text{B} = \text{O}\) (Oxygen radical),
\(\text{C} = \text{O}_3\) (Ozone).
Conclusion: The correct answer is (4) NO, O, and O\(_3\)
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]